Sunday 17 December 2017

RS Aggarwal Class 10 Solutions Arithmetic Progressions





Question 1:
The given progression is 3, 9, 15, 21 .....
Clearly (9 - 3) = (15 - 9) = (21 - 15) = 6 which is constant
Thus, each term differs from its preceding term by 6
So, the given progression is an AP
Its first term = 3 and the common difference = 6

Question 2:
The given progression is 16, 11, 6, 1, -4 ....
Clearly (11 - 16) = (1 - 6) = (-4 - 1) = - 5 which is constant
Thus, each term differs from its preceding term by - 5
So the given progression is an AP
Its first term = 16 and the common difference = - 5




RS AGGARWAL CLASS 10 SOLUTIONS ARITHMETIC PROGRESSIONS


RS AGGARWAL CLASS 10 SOLUTIONS ARITHMETIC PROGRESSIONS


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