Question 1:
Let AB be the tower standing on a level ground and O be the position of the observer. Then OA = 20 m and ∠OAB = 90° and ∠AOB = 60°
Let AB = h meters
From the right ∆OAB, we have
Hence the height of the tower is [latex]20\sqrt { 3 } m=34.64m [/latex]
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