Sunday, 20 August 2017

Right Circular Cone

Right Circular Cone


Right Circular Cone

If r, h and ℓ denote respectively the radius of base, height and slant height of a right circular cone, then-
  1.  2 = r2 + h2
  2. Area of base = πr2
  3. Curved (lateral) surface area = πrℓ
  4. Total surface area = πr (ℓ + r)
  5. Volume = 1/3 πr2h


NCERT Solutions for Class 9 Maths
http://www.learncbse.in/ncert-solutions-for-class-9-maths/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-number-system/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-2-polynomials/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-3-coordinate-geometry/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-linear-equations-in-two-variables/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-5-introduction-to-euclid-geometry/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-6-lines-and-angles/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-7-triangles/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-8-quadrilaterals/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-areas-of-parallelograms-and-triangles/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-10-circles/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-11-constructions/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-12-herons-formula/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-13-surface-areas-and-volumes/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-14-statistics/
http://www.learncbse.in/ncert-solutions-for-class-9-maths-chapter-15-probability/


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